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Set permission param

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Ensure permssion parameter is getting set when sharing a list
This commit is contained in:
NMerz
2020-11-14 12:46:33 -05:00
parent 2d3e985ded
commit 82272a9a29
4 changed files with 76 additions and 23 deletions
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14
Lambdas/Lists/ListShare/src/ListSharer.java
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@@ -22,7 +22,7 @@ public class ListSharer implements CallHandler {
}
final private String CHECK_ACCESS = "SELECT * from ListSharee WHERE listID = ? AND userID = ?;";
final private String SHARE_LIST = "INSERT INTO ListSharee(listID, userID) VALUES(?, ?);";
final private String SHARE_LIST = "INSERT INTO ListSharee(listID, userID, permissionLevel) VALUES(?, ?, ?);";
public Object conductAction(Map<String, Object> bodyMap, HashMap<String, String> queryString, String cognitoID) throws SQLException {
PreparedStatement checkAccess = connection.prepareStatement(CHECK_ACCESS);
@@ -52,15 +52,17 @@ public class ListSharer implements CallHandler {
throw new InputMismatchException("Could not find specified user to share with");
}
String shareWithSub = new String(invokeResult.getPayload().array()).replace("\"", "");
checkAccess.setString(2, shareWithSub);
checkAccessRS = checkAccess.executeQuery();
if (checkAccessRS.next()) {
throw new InputMismatchException("The specified user already has access");
}
// checkAccess.setString(2, shareWithSub);
// checkAccessRS = checkAccess.executeQuery();
// if (checkAccessRS.next()) {
// throw new InputMismatchException("The specified user already has access");
// }
PreparedStatement shareList = connection.prepareStatement(SHARE_LIST);
shareList.setInt(1, listID);
shareList.setString(2, shareWithSub);
Integer permissionLevel = Integer.parseInt(bodyMap.get("permissionLevel").toString());
shareList.setInt(3, permissionLevel);
shareList.executeUpdate();
connection.commit();
return null;